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Hence, the ball was thrown upwards with a velocity of 29.4 m s−1. (b) Let the maximum height attained by the ball be h. Initial velocity during the upward journey, u = 29.4 m s−1. Final velocity, v = 0. Acceleration due to gravity, g = −9.8 m s−2. From the equation of motion, (c) Ball attains the maximum height after 3 s.

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How we establish average height. The study of measurement of the human body, such as weight, standing height, and skinfold thickness, is called anthropometry. Move to a room with hard flooring (no carpet) and a wall that's clear of art or other obstructions. Remove your shoes and any clothing or...

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A ball is thrown vertically upward from the roof of a 64 foot tall building with a velocity of 96 ft/sec, its height in feet after t seconds is s(t) = 64 + 96 t - 16 t^2.' and find homework help for other Physics To find the maximum height of the ball, we first find the derivative of the function that defines the height.

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A ball is thrown straight upward and rises to a maximum height of 18.0 m above its launch point. at what height above its launch point has the speed of the - 10935541

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A ball is thrown straight upward and rises to a maximum height of 13.8 m above its launch point. At what height above its launch point has the speed of the ball decreased to one-half of its initial value?

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Feb 05, 2017 · A ball is thrown straight up with a speed of 12 meters per second near the surface of Earth. What is the maximum height reached by the ball?